Wednesday, 26 May 2010

(cos x)^2 + sin 2x = 0

(cosx)^2 + sin2x
= 0

We know that:

sin2x = 2sinx*cosx


==> cos^2 x + 2sinx*cosx = 0

Facros cos(x):


==> cosx*(cosx + 2sinx) = 0

Then :

cosx = 0  
OR   cosx + 2sinx = 0

cosx = 0 ==> x=pi/2 ,
3pi/2

cosx + 2sinx = 0

==> cosx =
-2sinx

==> -cosx/2 = sinx

Divide by cosx


==> -1/2 = tanx

==> tanx = -1/2


==> x= -arcttan (1/2)

No comments:

Post a Comment

To what degree were the U.S., Great Britain, Germany, the USSR, and Japan successful in regards to their efforts in economic mobilization during the...

This is an enormous question that can't really be answered fully in this small space. But a few generalizations can be made. Bo...