Tuesday, 3 April 2012

Find the foci of the hyperbola? `x^2/64-y^2/36=1`

If general
equation of hyperbola is

`x^2/a^2+y^2/b^2=1`

then we can
calculate linear eccentricity `e>0` by using formula

`e^2=a^2+b^2`     
 ...


at

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