Given
,
By applying Integration by
parts we can solve the given integral
so,
let
sqrt(1-x^2) ,v' = (1/x^4)
=>
=> =
let
so,
=
(sqrt(t))
= [as
(dt)/dx
=
=
=
=
so, and as
so
=
=
=
=
so , let us see the values
altogether.
and
,v=-(1/(3x^3))
Now ,by applying the integration by
parts is given as
then,
=
(-(1/(3x^3))) - int (-x/sqrt(1-x^2))(-(1/(3x^3))) dx
=
(-(1/(3x^3))) -(-...
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