Solve the following by elimination method: 2x - 3y = 5 3x - (2y-3)/5 = 4

(1)
2x-3y=5
(2) 3x-(2y-3)/5=4

Simplify (2)
(5)3x - (5)(2y-3)/5
= 4(5)
15x - 2y + 3 = 20
(3) 15x - 2y = 17

2x - 3y = 5
multiply by -2 to get -4x + 6y = -10   (4)
15x - 2y = 23 multiply by 3 to get 45x - 6y
= 51   (5)

Now add (4) and (5) to get

41x = 41  and
solving for x we get

x = 1

To find y we substitute x = 1
into (1) and solve for y
2(1)-3y=5

3y = 2 - 5
3y =
-3
y = -1

Check the answers in the 2nd
equation
3x-(2y-3)/5=4
3(1) - (2(-1)-3)/5 = 4
3 - (-5)/5 =
4
3 - (-1) = 4
4 = 4  Checks...

So our answer is (1,
-1)