e^2x-3e^x +2 =0
Let us assume that e^x =y.
Now substitute:
==> y^2 -3y +2 =0
Factorize:\
(y-2)(y-1)=0
y1= 2==> y1=e^x1= 2 ==> x1=ln2
y2=1==> y2=e^x2= 1 ==> x2=0
The solution for the equation is :
x= {0, ln2}
This is an enormous question that can't really be answered fully in this small space. But a few generalizations can be made. Bo...
No comments:
Post a Comment