If 38% of a number "n" is 24.32, what is 20% of n?

Let's
think of this question as:

x% of n is a, then what is y% of n.

x% of n can be written as (x/100) * n.

This means (x/100)*n =
a

Using this relation, we can find the value of n as:

n =
a/(x/100) = 100a/x

Then we can find the y% of n as (y/100)*n

From the given data, x = 38, a = 24.32 and y = 20.

Thus, using the
above discussion, n = 100a/x = (100 * 24.32)/38

= 64.

Thus, the number n has a value of 64.

20% of n (or 64) is calculated
as (20/100) * n = (20/100) * 64 = 12.8.

The
second part of the question can also be similarly solved.

(38/100) * n =
25.32

this means, n = 25.32*100/38 = 66.63

And 20% of n =
(20/100) * n = (20/100) * 66.63 = 13.33.

As shown above, any such numerical can be solved by using the procedure
detailed here.

Another way of solving this problem is without calculating the
value of "n", since this was not needed. Revisiting the problem:

If
x% of n is a, what is its y%.

From the above discussion, n = (a*100)/x

and y% of n = (y/100) * n

Substituting the value of n
from above in this equation, we get

y% of n = (y/100) * (a*100)/x =
(y*a)/x.

For the first part of the question, 20% of n = (20*24.32)/38 =
12.8

which the same answer we got earlier.

Hope this helps.