`int_-5^5(x - sqrt(25 - x^2))dx` Evaluate the integral by interpreting it in terms of areas.

gsarora17

`int_-5^5(x-sqrt(25-x^2))dx`

`=int_-5^5xdx-int_-5^5sqrt(25-x^2)dx`

`=I_1-I_2`

I_1 can be be interpreted as area of two triangles;one above the x-axis and the other
below axis.Since they are on...

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