From the given
line equation: x-y=8, express it in slope-intercept form (y=mx+b).
x-y
=8
+y +y
---------------
x =
8+y
-8 -8
----------------
x -8
=y Or y = 1x-8 where slope
Note that perpendicular
lines follows
Then
Determine the other line equation using and that will pass through point
(2,1).
Plug-in the values in y=mx+b
1 = (-1)(2)+b
1= -2 +b
+2 +2
------------------
3 =b
Line
equation: y=-1x+3 or x+y =3 based from and b =3
the two lines are
x-y=8 and x+y =3.
Applying elimination method to solve for x.
x-y=8 Add the to equations.
+ x+y
=3
-------------
2x = 11 Cancels
out y's since -y+y = 0.
Divide both sides by 2
to isolate x.
To solve for y, subtract
the equations as:
x -y = 8 Or x -y =8
- ( x +y =3) -------> + (-x -y = -3 ). Subtraction rules of
signs.
-----------------
-2y =
5
Divide both sides by -2 to isolate
y.
Intersection point:
(11/2, - 5/2)
This is the same as (5.5, -2.5)
No comments:
Post a Comment