Water is leaving a hose at 6.8 m/s. If the target is 2 m away horizontally, what angle should the water leave the hose at? Answer is supposed to...

Let us say the
angle to ground is theta;

Using equation of motion;

`rarr
S = ut+1/2at^2`

At horizontal direction a = 0

`2 =
6.8costhetaxxt ----(1)`

 

`uarr S = ut+1/2at^2`

There is no vertical distance for the...

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