`y = ln|csc(x)|` Find the derivative of the function.

`y=ln|csc(x)|`

To take the
derivative of this, use the formula:

`(ln u)' = 1/u*u'`

Applying that, y' will be:

`y'=1/(cscx)*(cscx)'`

Take note that the derivative of cosecant is `(csctheta)' = -cscthetacottheta`
.

`y'=1/cscx*(-cscxcotx)`

`y'=-cotx`

 

Therefore, the derivative of the given function is
`y'=-cotx` .